Colonel W. Marshall of the 79th Regiment of Foot

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Colonel W. Marshall of the 79th Regiment of Foot  Click on the tune title to see or modify Colonel W. Marshall of the 79th Regiment of Foot's annotations. If the link is red you can create them using the form provided.Browse Properties <br/>Browse/:Colonel W. Marshall of the 79th Regiment of Foot
 Theme code Index    5555 1H3H62
 Also known as    
 Composer/Core Source    William Marshall
 Region    Scotland
 Genre/Style    Scottish
 Meter/Rhythm    Strathspey
 Key/Tonic of    C
 Accidental    NONE
 Mode    Ionian (Major)
 Time signature    4/4
 Structure    AB
 Editor/Compiler    William Marshall
 Book/Manuscript title    1845 Collection
 Tune and/or Page number    p. 14
 Year of publication/Date of MS    1845
 Title of recording    
 Record label/Catalogue nr.    
 Year recorded    
 Score   ()   

COLONEL W. MARSHALL OF THE 79th REGIMENT OF FOOT. Scottish, Strathspey. C Major. Standard tuning (fiddle). AB. Composed by William Marshall (1748-1833). The 'Colonel' the composer names in the title was his third (and only surviving) son, also named William, who served in the Napoleonic Wars and lost his right arm at the battle of Quatre Bras, just prior to Waterloo. He retired to live in the house built by his father, Newfield, and was remembered as a popular figure in the district of Aberlour/Craigellachie in his later years (Cowie, The Life and Times of William Marshall, 1999). It was he who honored his father with a gravestone in Bellie Cemetery, Fochabers. The Colonel's regiment, the 79th Regiment of Foot was also known as The Queen's Own Cameron Highlanders, and although a Scottish regiment it usually had a number of Englishman in it at any one time (Farwell, 1981).

Printed source: Marshall, Fiddlecase Edition, 1978; 1845 Collection; p. 14.

T:Colonel W. Marshall of the 79th Regiment of Foot
S:Marshall - 1845 Collection
Z:AK/Fiddler's Companion
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e/f/|g>a g<e g>a g<e|(fg/a/) (a/g/)f/e/ fdd(e/f/)|g>a g<e c>d c>G|(A<a) (g>f) e2 de/f/|
g>a g<e g>a g<e|(fg/a/) (a/g/)f/e/ fdd(e/f/)|c>d c<G A>c (B/A/)(G/F/)|E>G c/e/g/e/ d2c||